The wiki seems to imply Turing-completeness because no restrictions on jumps are specified here https://ripple.com/wiki/Contracts#Foundational_Ops.
Which is it and what (if any) is the actual intention ?
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1Cool, I didn't even know Ripple had contracts! – ripper234 Mar 22 '13 at 08:43
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1If the language is Turing complete, they will promptly have to be disabled :-) – Alex Kravets Mar 22 '13 at 09:33
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It should be Turing complete. However, every time a contract is invoked, the maximum number of operations the contract can perform is limited. Operations that access a contract must specify an operation count limit to get a limit higher than the default. Higher limits require higher transaction fees.
David Schwartz
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Does the Turing completeness of Ripple allow for denial of service attacks with infinite loops? – makerofthings7 Dec 15 '13 at 01:35
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@makerofthings7 No, there's a strict limit on how much work a contract can do. – David Schwartz Feb 23 '14 at 21:28